Heat from reservoirs is absorbed at temperatures:

T_{1}=1000 K

T_{2}=800 K

T_{3}=600 K

Let heat from those reservoirs be Q_{1},Q_{2} and Q_{3} respectively.

Now, Workdone by Engine :

W = 10 kw

Heat Rejected : Q_{4}=400 kj/min

At Temp : T_{4}=300 K

Net Heat -> Q = Q_{1}+Q_{2}+Q_{3}

_{}
But we dont have Q_{1}, Q_{2} or Q_{3}.

Q = W + Q_{4} = 10kw + 400 kj/min

1 kw=60 000 J / min -> 10 kw = 600 KJ / min

Q = 600 + 400 = 1000 KJ/min

Also from question :

Heat from reservoir at 1000K = 60% of heat from reservoir at 600K

that is : Q_{1}=0.6Q_{3}

Now,

Q = Q_{1} +Q_{2} + Q_{3}

_{}
1000 = 0.6Q_{3 }+Q_{2 }+Q_{3}

Q_{2}=1000 - 1.6Q_{3}

Apply Clausius theorem to find values of Q_{1} , Q_{2} and Q_{3}

Q_{1}/T_{1} + Q_{2}/T_{2} + Q_{3}/T_{3} = Q_{4}/T_{4}

_{}

0.6Q_{3}/1000 + (1000 - 1.6Q_{3})/80 + Q_{3}/600 = 400/300

**Q**_{3} = 312.5 kJ / min

**Q**_{1} = 0.6 * 312.5 = 187.5 kJ/min

we have , Q_{2}=Q - (Q_{1}+Q_{3})

Q_{2} = 1000 - (312.5 + 187.5 )

**Q**_{2} = 500 kJ / min

**Thus we have heat absorbed from each reservoir as Q**_{1},Q_{2} and Q_{3} .

Thanks